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Roethlisberger named AFC Offensive Player of the Week

Pittsburgh Steelers quarterback Ben Roethlisberger has been named AFC Offensive Player of The Week for his performance against the Cleveland Browns in week 17.
In Pittsburgh’s 41-9 win over the Cleveland Browns, Roethlisberger went 15 of 22 for 280 yards and threw 2 touchdowns, including a 56 yard TD strike to Mike Wallace on the first play of the game.
Roethlisberger has gone 158 consecutive attempts without throwing an interception.

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