Pittsburgh Steelers quarterback Ben Roethlisberger has been named AFC Offensive Player of The Week for his performance against the Cleveland Browns in week 17.
In Pittsburgh’s 41-9 win over the Cleveland Browns, Roethlisberger went 15 of 22 for 280 yards and threw 2 touchdowns, including a 56 yard TD strike to Mike Wallace on the first play of the game.
Roethlisberger has gone 158 consecutive attempts without throwing an interception.

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